Question: ??????? [ P=4,000 int_{0}^{6} t e^{-0.1 t} d t ] with ( P ) in dollars and ( t ) in years. Find the present

??????? \[ P=4,000 \int_{0}^{6} t e^{-0.1 t} d t \] with $ P $ in dollars and $ t $ in years. Find the present value (in dollars). (Round your answer to the nearest cent.) 2 answers

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