Pairing between identical nucleons is caused by a residual interaction in addition to the central potential $V(r)$ and leads to the fact that identical nucleons couple pair$-$wise to $J=0.$

The effed of Pairing manifests itself in the isotopes Binding energies by influencing the stability of nuclei Consider the masses $($or binding energies$)$ of the isotopes ${?}^{58}Ni,{?}^{59}Ni,$ and ${?}^{60}Ni.$ How does the effect of pairing manifest itself?

Even$-$mass isoiopes have higher Binding energies per nuckons dive to the formatron of stable pairs of nucleons

where$-$as ocld$-$mass isotopes hate slightly lower Binding energies per nucleons due to unpatired nudeons that do not fully bene fit's from the attraclive force associated with pairing.

Identical nuclecni can form pars' with opposite spin lexing to lower eneggy states in the nideus. The odd nudeons can not form apair.

The paining is caused by the residual strong force $($Atircelive Foroe$)$ that ads between nucleonis

$N{i}_{28}^{58}$

obrace$(28{)}^{59}$

${?}_{Ni}^{Ni}$

$-2$ nucleons are occupying $(2p_3{)}^2$

$-3$ nucleons are occupying

$-4$ nucleons are occupying $(2\frac{p_3}{2}{)}^2$

Binding Energy $E_B=M{(}^{58}{N}_i)-[M{(}^{54})+2mn]$

Binding Enegy $E_B=M{(}^{59}N{i}_i)-[M{(}^{56})+3m{i}_n]$

Binding Energy $E_B=M{(}^N)-[M{(}^{56})+4mn]$

$E_{Bv}-29\mathrm{.}75$MeV

$E{B}^2=-29\mathrm{.}26$MeV

$E_B=42\mathrm{.}85$MeV

is this correct for the following question?