Question: Parallelize this code, calculate speedup and efficiency of the parallel code: import java.util.Scanner; //This class will calculate the max and min values of the array
Parallelize this code, calculate speedup and efficiency of the parallel code:
import java.util.Scanner;
//This class will calculate the max and min values of the array
class TestArray
{
int MAX(int[]Arry)
{
int maxValue= Arry[0];
for(int i=1;i
{
if(Arry[i]>maxValue)
{
maxValue=Arry[i];
}
}
return maxValue;//This method will return the max value present in the array.
}
int MIN(int[]Arry)
{
int minValue=Arry[0];
for(int i=1;i
{
if(Arry[i]
{
minValue=Arry[i];
}
}
return minValue;
}
}
public class DifferenceArry
{
public static void main(String[] args)
{
int n;
//It creates scanner object
Scanner sc = new Scanner(System.in);
System.out.print("Enter the array elements:" );
n=sc.nextInt();
int arr[]=new int[n];
for(int i=0;i
{
System.out.print("Enter ["+(i+1)+"] element :" );
arr[i]=sc.nextInt();
}
TestArray obj=new TestArray();
System.out.println("Maximum value in the array is :" +obj.MAX(arr));
System.out.println("Minimum value in the array is :" +obj.MIN(arr));
int diff=obj.MAX(arr)-obj.MIN(arr);
System.out.print("Difference between max and min elements is : " +diff );
}
}
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