Question: Part 1 ets m = f ' ( x 0 ) . Note that y = l n ( x 3 - 7 ) is

Part 1ets m=f'(x0).
Note that y=ln(x3-7) is a cempoution, and so me must use the Chain flule ddr[f(g(x))]=r(g(x))g(x) to find its derivative.
The "inide function is x3-7 and the "outside" fusction is
Part 1 ets m = f ' ( x 0 ) . Note that y = l n (

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