Question: Part 2 Disk plus ring Mass of ring (Mring): 1. 440 kg Inner radius of ring (R1): _ 0545 m Outer radius of ring (R2):

 Part 2 Disk plus ring Mass of ring (Mring): 1. 440

Part 2 Disk plus ring Mass of ring (Mring): 1. 440 kg Inner radius of ring (R1): _ 0545 m Outer radius of ring (R2): 0 . 063 m 20g Force of kinetic friction fx = 2 N Angular Tension FT -fk Net torque Theoretical Experimental acceleration Frin (N) net = r(FT - fk) moment of inertia moment of inertia a =" string (N.m) I = 1/2 MdiskRdisk? I = [nella = r(FT - fk)/ (rad/s2) (N) + 1/2 Mring(R12 + R2- (kg.m2) (kg.m?) Trial 1 0. 734 1. 990 1.799 0. 0117 0. 0145 0. 0159 Trial 2 0 . 679 1.999 1. 799 0. 0117 same as above 0 . 0172 Trial 3 0 . 650 1.999 1.799 0. 0117 same as above 0 . 0180 Trial 4 0.628 1.99 9 1.799 0 . 0117 same as above 0. 0186 Trial 5 0. 681 1. 99 9 1.799 0 . 0117 same as above 0 . 0172 Mean experimental moment of inertia: . 01738 kg.m2 Standard deviation: _. 00 102 kg.m2 QUESTIONS Part 1 1. In your data table in Part 1 you have two values for the moment of inertia. One is found Part 2 1. In your data table in Part 2, you have two values for the moment of inertia. One is found from the theoretical equation for moment of inertia that is introduced in the Theory section and the other is an average experimental value obtained using Newton's 2nd law for rotational motion, Tner = Ia, in conjunction with the definition of torque, t = rF. How well do your two values agree with each other? What is the percent difference? Does the theoretical value fall within one standard deviation of the experimental value

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