Question: Part 2 - Find the error(s) and solve the problem correctly. Explain your corrections. Solve for 2cos x = 4 cos x sin ^2x Answer:

Part 2 - Find the error(s) and solve the problem correctly. Explain your corrections.

Solve for 2cos x = 4 cos x sin ^2x

Answer: 2 cos x= 4 cos x sin ^2x

2 cos x = 4 cos x sin ^ 2 x (2 cos x is common on both sides)

sin x =1 and angle is pi/2.

x=pi/2

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