Part $3$: Friend Function

Consider the following Employee class:

$//$Employee$.$h

class Employee

$\{$

private:

string name;

double salary;

public:

Employee$($string n$,$ double s$)$;

string getName$()$;

double getSalary$()$;

friend bool operator$==($Employee&$,$ Employee&$)$;

friend void operator$+=($Employee& e$1,$ Employee& e$2)$;

$\}$;

bool operator$==($Employee& e$1,$ Employee& e$2)$

$\{$

return $($e$1.$name $==$ e$2.$name$)$;

$\}$

void operator$+=($Employee& e$1,$ Employee& e$2)$

$\{$

e$1.$salary $+=$ e$2.$salary;

$\}$

$//$main$.$cpp

#include $$Employee$.$h$$

int main$()$

$\{$

Employee e$1("$Bob$",50)$;

Employee e$2("$Bill$",50)$;

cout $<<($e$1==$ e$2)<<$ endl;

e$1+=$ e$2$;

cout $<<$ e$1.$getSalary$()<<""<<$ e$2.$getSalary$()<<$ endl; $//10050$

return $0$;

$\}$

Compile and run the programs.

Your Turn:

$(2$ pts$)$ Declare a private static member variable named count in the Employee class, whenever the new object has created, increment the $$count$$ variable. In addition, add a method named $$getCount$()$ that returns the value of this static variable.

$(5$ pts$)$ Overload the $+$ operator as a friend function that needs two Employee objects as parameters, adds two employee$$s names and salaries, assign them to new employee object, and then return new employee object.

$(3$ pts$)$ The main function declares three objects of Employee. Add the first two employee objects and then display the third employee$$s name and salary to the screen. In addition, display the value of static variable count.