Part A: Average Velocity and Average Acceleration Given the position-versus time graph, find the velocity-versus time graph and acceleration vs. time graph. 0.9 0.8 0.7 0.6 ICOL Position (m 0.5 04 0.3 0.2 0.1 0 0 0.4 0.8 1.2 1.6 Time (s) 1. What is the average velocity (slope) at the interval Os to 0.5s? What can you say about its magnitude and direction? EX. 1 m/s, Constant and positive velocity 8 L 2. What is the average (slope) at the interval 0.5s to 1.0s? What can you say about its magnitude and direction? 3. What is the average velocity (slope) at the interval 1.0s to 2.0s? What can you say about its magnitude and direction? 4. Plot the calculated Velocity vs. Time average velocity in the N figure at the right and 1.5 describe its trend. 5. What does the horizontal 0.5 Velocity (mis) line on a velocity versus time graph represents -0.5 PART 0 0.2 0.4 0.6 0.8 1 1.2 1.4 1.6 1.8 2 Time (s) 6. " What is the average acceleration (slope) at interval Os to 0.5s, 0.5s to 1.0s, and 1.0s to 2 0s? What can you say about their magnitudes and directions? 7. Plot the calculated average Acceleration vs. Time velocity in the figure at the right and interpret its 1.5 meaning. 0.5 Acceleration (m/s) 05 -1 REG 0 0.2 0.4 0.6 0.8 1 1.2 1.4 1.6 1.8 2 Time (S)PART B. Instantaneous velocity and Instantaneous acceleration Consider the motion of a particle in which the position is x(t) = 3.0t - 3t* m. 1. What is the position of the particle at t = 0.25 s, t = 0.50 s, and t = 1.0 s? Strategy: Substitute time to the position x(t) L 2. Plot the calculated values in the position x(t) vs. time (t) graph .0.5 -1 1.5 -2 2.5 0.5 1.5 Time (s) 3. What can you say about the magnitude and direction at t = 0.25 s, t = 0.50 s, and t = 1.0 s? Describe and interpret the meaning of the graph. 4. Find the functional form of velocity. P Ex. Finding the functional form of velocity. UCATION DEP The position of a particle is given by x(t) = 3.0t + 0.5f m. Strategy. use dx(t)/dt = nAt - ! Solution: v(t) = dx(t)/dt= 3.0 + 1.50 m/s 5. What is the instantaneous velocity at t = 0.25 s, t = 0.50 s, and t = 1.0 s? Strategy: Substitute time to the functional form of velocity derived. 8 6. Plot the calculated values in the velocity v(t) vs. time (t) graph REGION velofty (HAS) 0.5 1.5 Time (s)6. Plot the calculated values in the velocity v(t) vs. time (t) graph REGION velofty (FR/S) N 6 0 0.5 1.5 Time (S) 10 7. What can you say about the magnitude and direction at t = 0.25 s, t = 0.50 s, and t = 1.0 s? Describe and interpret the meaning of the graph. 8. Find the functional form of acceleration. EX. Strategy: use dx(t)/dt = nAt" " ' Solution: a(t) = dv(t)/dt= 3t m/s 9. What is the instantaneous acceleration? 10. Plot the calculated value in the acceleration a(t) vs. time (t) graph. Acceleration vs. Time Interpret the meaning of the graph. NA TMENT NO att) (mis) DEPA 0.5 1 1.5 1,75 Time (S)