Part A Give the mass of the solute and the volume of the solvent for 1.70...
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Part A Give the mass of the solute and the volume of the solvent for 1.70 L of 0.100 M (NH4)2SO4 solution, starting with solid (NH4)2SO4 Express your answers to three significant figures separated by commas. 195 ΑΣΦρά ο m((NH,),SO4), V(H,O) 24.2,1.70 Submit Previous Answers Request Answer ? 8, L 4 * Incorrect; Try Again; 12 attempts remaining The molarity and the desired volume of the solution are given. Molarity is moles of solute per liters of solution, and the mass ( m) can be calculated using the number of moles (n) and the molar mass (.) of a substance using the relationship m = nxM. The definition of molarity and the relationship between mass and moles are then used to find the mass of ammonium sulfate needed to achieve the desired concentration ► Part A Give the mass of the solute and the volume of the solvent for 1.70 L of 0.100 M (NH4)2SO4 solution, starting with solid (NH4)2SO4 Express your answers to three significant figures separated by commas. 195 ΑΣΦρά ο m((NH,),SO4), V(H,O) 24.2,1.70 Submit Previous Answers Request Answer ? 8, L 4 * Incorrect; Try Again; 12 attempts remaining The molarity and the desired volume of the solution are given. Molarity is moles of solute per liters of solution, and the mass ( m) can be calculated using the number of moles (n) and the molar mass (.) of a substance using the relationship m = nxM. The definition of molarity and the relationship between mass and moles are then used to find the mass of ammonium sulfate needed to achieve the desired concentration ► Part A Give the mass of the solute and the volume of the solvent for 1.70 L of 0.100 M (NH4)2SO4 solution, starting with solid (NH4)2SO4 Express your answers to three significant figures separated by commas. 195 ΑΣΦρά ο m((NH,),SO4), V(H,O) 24.2,1.70 Submit Previous Answers Request Answer ? 8, L 4 * Incorrect; Try Again; 12 attempts remaining The molarity and the desired volume of the solution are given. Molarity is moles of solute per liters of solution, and the mass ( m) can be calculated using the number of moles (n) and the molar mass (.) of a substance using the relationship m = nxM. The definition of molarity and the relationship between mass and moles are then used to find the mass of ammonium sulfate needed to achieve the desired concentration ►
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To solve this problem we need to calculate both the mass of the solute NH42SO4 ammonium sulfate and ... View the full answer
Related Book For
Chemistry The Central Science
ISBN: 978-0321696724
12th edition
Authors: Theodore Brown, Eugene LeMay, Bruce Bursten, Catherine Murphy, Patrick Woodward
Posted Date:
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