Question: Part a: Solve for the forces in the cables AB and BC in terms of the weight of the hanging mass. Part b: Solve for

Part a: Solve for the forces in the cables AB and BC in terms of the weight of the hanging mass.
Part b: Solve for the forces in the cables AB and BC in terms of the weight of the hanging mass.
Part c: Find the maximum mass that can be supported. (The answer should be in kg)
Two high-strength steel rods of different diameters are attached to points A and C and support a
mass M at point B, as shown in Figure 3.1. The ultimate strength, i.e., the stress at which fractur
occurs, of the two rods is ult. Rod AB has a cross sectional area of AAB and rod BC has a cros
ectional area of ABC. What is the maximum mass M that can be supported?
Take AAB=200mm2 and ABC=
350mm2
Take ult=300MPa,a=275
mm.
Part a: Solve for the forces in the cables AB and

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