Part A String 1 in the figure has linear density 2.50 g/m and string 2 has linear density 3.30 g/m . A student sends pulses in both directions by quickly pulling up on the knot, What should the string length In be? then releasing it. She wants both pulses to reach the ends of the strings simultaneously. Express your answer with the appropriate units. (Figure 1) HA ? Value m Submit Request Answer Part B What should the string length L2 be? Express your answer with the appropriate units. ? Value m Submit Request AnswerFigure 4 m String 1 String 2 Knot LSolis Given : String 1 has lineas density = 2.50 8/ m = 250 NO 18/m string 2 has linear density = 3:30 g/m = 3:30 *10 kg/m The speed of wave in a string V Z Z The time taken to Paved the wave from knot to end of the string + ( LI) LI * = & the time taken to travel the wave from knoy to end of the string 2 ( 12) L2 Now, the time in same - 2 JI = L2) - LI = 3: 30 * 10 3 2.50 * 10 -3 ( L2 ) = 51.32 (L2 ) 7 L 1 = 1 . 14 L 2 Total length of string L = 4 m 7Lith = y 1 . 14 ( 2 + Ly = 4 -) 2.14 L2 = 4 4 = 1:869 m = ) L 2 = 2.14 Then, L = 1. 14 62 = 1. 14 X 1. 869 - ) Ly = 2. 130 m Hence, ( a) The string length L, = 2.130 m ( 6 ) The string length L2 = 1.869 m