Part A $-$ Using the definition for mole fraction.

A solution was prepared by dissolving $165\mathrm{.}0g$ of $KCl$ in $315g$ of water.

Calculate the mole fraction of $KCl.($The formula weight of $KCl$ is $74\mathrm{.}6\frac{g}{m}ol.$ The formula weight of water is $18\mathrm{.}0\frac{g}{m}ol.)$

Express the mole fraction of $KCl$ to two decimal places.

View Available Hint$($s$)$

$=$

Part B $-$ Use the definition of molality

A solution was prepared by dissolving $165\mathrm{.}0g$ of $KCl$ in $315g$ of water.

Calculate the molality of $KCl.($The formula weight of $KCl$ is $74\mathrm{.}6\frac{g}{m}ol.$ The formula weight of water is $18\mathrm{.}0\frac{g}{m}ol.)$

Express the concentration of $KCl$ in molality to two decimal places.

View Available Hint$($s$)$

$0\mathrm{.}11mo\frac{l}{k}g$

$0\mathrm{.}01mo\frac{l}{k}g$

$0\mathrm{.}14mo\frac{l}{k}g$

$7\mathrm{.}02mo\frac{l}{k}g$