Question: Part A What magnitude charge creates a 2.50 N/C electric field at a point 1.90 m away? Express your answer with the appropriate units. ?

 Part A What magnitude charge creates a 2.50 N/C electric fieldat a point 1.90 m away? Express your answer with the appropriateunits. ? Value Units Submit Request AnswerWhat is the strength of theelectric field 3.0 cm from a small plastic bead that has beencharged to -9.0 nC? Express your answer with the appropriate units. HA? E= Value Units Submit Request Answer Part B What is thedirection of the electric field 3.0 cm from a small plastic beadthat has been charged to -9.0 nC? O towards the bead Oaway from the beadPart A The electric field at a point inspace is E =( 100 i + 300 j) N/C. What isthe -component of the electric force on a proton at this point?

Part A What magnitude charge creates a 2.50 N/C electric field at a point 1.90 m away? Express your answer with the appropriate units. ? Value Units Submit Request AnswerWhat is the strength of the electric field 3.0 cm from a small plastic bead that has been charged to -9.0 nC? Express your answer with the appropriate units. HA ? E= Value Units Submit Request Answer Part B What is the direction of the electric field 3.0 cm from a small plastic bead that has been charged to -9.0 nC? O towards the bead O away from the beadPart A The electric field at a point in space is E =( 100 i + 300 j) N/C. What is the -component of the electric force on a proton at this point? Express your answer with the appropriate units. View Available Hint(s) HA ? (F)x = Value UnitsV Part B The electric field at a point in space is E =( 100 What is the y-component of the electric force on a proton at this point? i + 300 j) N/C. Express your answer with the appropriate units. View Available Hint(s) HA ? (F)y = Value UnitsThe electric field at a point in space is E =( 100 Part D i + 300 j) N/C. What is the y-component of the electric force on an electron at this point? Express your answer with the appropriate units. View Available Hint(s) LA ? (F)y = Value UnitsWhat is the magnitude of the proton's acceleration? Express your answer with the appropriate units. The electric field at a point in space is E =( 100 View Available Hint(s) i + 300 j) N/C. Hint 1. How to approach the problem Use your answers to parts A and B to determine the magnitude of the force on the proton. Then apply Newton's second law to find the proton's acceleration. The proton's mass is 1.67 x 10 27 kg Hint 2. Simplify: magnitude of force HA ? ap Value UnitsPart A What is the strength of an electric field that will balance the weight of a 1.1 g plastic sphere that has been charged to -4.7 nC? Express your answer with the appropriate units. View Available Hint(s) Hint 1. How to approach the problem Write Newton's second law for the plastic sphere and express the electric field strength. > Hint 2. Simplify: Newton's second law HA ? E Value UnitsPart B What is the direction of an electric field that will balance the weight of a 1.1 g plastic sphere that has been charged to -4.7 nC? View Available Hint(s) Hint 1. How to approach the problem Consider what direction the electric force has and take into account the sign of the sphere's charge to determine the electric field's direction. > Hint 2. Simplify: electric field direction upward O downwardV Part A A 8.0*10 2g honeybee acquires a charge of +21pC while flying. The earth's electric field near What is the ratio of the electric force on the bee to the bee's weight? the surface is typically (100 N/C, downward). AEd O ? Fe FGPart B A 8.0*10 2g honeybee acquires a charge of +21pC while flying. The earth's electric field near What electric field (strength) would allow the bee to hang suspended in the the surface is typically (100 N/C, downward). Express your answer with the appropriate units. 0 ? E= Value UnitsA8.0*10 2g honeybee acquires a charge of +21pC while flying. The earth's electric field near the surface is typically (100 N/C, downward). Part C What electric field (direction) would allow the bee to hang suspended in the air? O The electric field must be directed downward. O The electric field must be directed upward

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