Question: Part b: Create a DFA M, such that: (a) M accepts all strings which begin with b but do not contain the substring bab. (b)

Part b: Create a DFA M, such that: (a) M accepts

Part b:

all strings which begin with b but do not contain the substring

Create a DFA M, such that: (a) M accepts all strings which begin with b but do not contain the substring bab. (b) L(M)={aibjcki+j+k is odd },={a,b,c} Create an NFA which accepts all strings in which the third last character is an a. Then via subset construction, create an equivalent DFA. Show all your work

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