Question: PART B - MASS TRANSFER A 4 c m 3 mixture formed by adding 2 c m 3 of acetone ( C H 3 -

PART B - MASS TRANSFER
A 4cm3 mixture formed by adding 2cm3 of acetone (CH3-CO-CH3) to 2cm3 dibutyl phthalate (CO2C4H9-C6H4-CO2C4H9) is contained in a 6mm diameter vertical glass tube immersed in a thermostat maintained at 42C. A stream of air at 42C and 101.325kPa pressure is passed over the open top of the tube to maintain a zero-partial pressure of acetone vapor at that point. The liquid level is initially 11.5mm below the top of the tube and the acetone vapor is transferred to the air stream by molecular diffusion alone. The dibutyl phthalate can be regarded as completely non-volatile and the partial pressure of acetone vapor may be calculated from Raoult's law on the assumption that the density of dibutyl phthalate is sufficiently greater than that of acetone for the liquid to be completely mixed.
Assuming the vapor is ideal and neglecting the effects of bulk flow in the vapor, calculate the time taken for the liquid level to fall to 5cm below the top of the tube.
DATA: Vapor pressure of acetone at 42C=60.5kPa
Diffusivity of acetone vapor in air at 42C=0.123cm2s
Density of liquid acetone =764kgm3
Density of liquid dibutyl phthalate =1048kgm3
 PART B - MASS TRANSFER A 4cm3 mixture formed by adding

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