Part C: Carefully study the following data definitions, and assuming data segment starts at address $0$x$10008000,$ answer the next $4$ questions. $\{6$x$1=6$ pts $\}$

$.$data

X: $.$byte $-10$

Y: $.$word $0$x$6$c$4$f$903$e$,0$X$22334455$

arr: $.$half $0$x$9$a$2$c$,0$xac$89,0$x$9876,0$xC$000,-1$

a: $.$double $80\mathrm{.}75$

b: $.$float $-20\mathrm{.}0$

res: $.$float $0\mathrm{.}0$

$1)$

The number of bytes $($in DEC$)$occupied by the data segment is $40$ bytes.

$2)$

The address $($in HEX$)$of the variable Y will be $0$x$10008004$ and the address of the variable b $($in HEX$)$ will be $0$x$10008020$

$3)$

What will be in $($HEX$)$ in registers $t$1,$ $t$2,$ and $t$3$ after executing the following code?

la $t$0,$ X

lh $t$2,10($$t$0)$ # $t$2=0$x$00002233$

lw $t$3,4($$t$0)$ # $t$3=0$x$6$c$4$f$903$e

$4)$

At the time when the CPU is executing the instruction at memory address $0$x$00002$F$08,$ the pc register contains $($in HEX$)0$x$00002$F$08+4=0$x$00002$F$0$C