Part D - Capacitors in Series [Digits title here ] voltage (v) Run #20 Run # 20 -0.28V 1.8 1.6 Inverse Exponent A( 1-e*(-B(t-t.)) ) + C 1.2 A = -11300 B - -2.60x10* to = 0.00 1.0 C = 0.939 RMSE = 0.135 Voltage (V) O.B 0.6- 0.4- -0.2 -0.4 -0.6- 0.0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 Time (s) 1. Calculate the net capacitance Ceq. Show your work. 2. Make sure you find the voltage across both capacitors. This will involve moving one or both of the leads to the voltage sensor. 3. Find and state the net resistance 4. Determine the Capacitance from the graphs using either the charging or discharging method as before and compare it to your value from step C.2. Are they in agreement? Why or why not? 5. Quantitatively compare cake and Texp.Circuit Elements Circuit Element Value Error Battery 2.0 V ?? V Resistor 330 Q ?? Q Capacitor 1 1000 HF ?? UF (black) Capacitor 2 220 UF ?? UF blue