Question: Part E- At t_(1)=5.0s an object's velocity is v_(1)=8.890(m)/(s) to the EAST, and at t_(2)=9.0s its velocity is v_(2)=14.650(m)/(s) to the WEST. Assuming a constant

Part

E-

At

t_(1)=5.0s

an object's velocity is

v_(1)=8.890(m)/(s)

to the EAST, and at

t_(2)=9.0s

its velocity is

v_(2)=14.650(m)/(s)

to the WEST. Assuming a constant acceleration, Take EAST as the positive direction. What is its acceleration with a proper sign? Keep 3 digits after the decimal point.

 Part E- At t_(1)=5.0s an object's velocity is v_(1)=8.890(m)/(s) to the

Part E - At t1=5.0s an object's velocity is v1=8.890m/s to the EAST, and at t2=9.0s its velocity is v2=14.650m/s to the WEST. Assuming a constant acceleration, Take EAST as the positive direction. What is its acceleration with a proper sign? Keep 3 digits after the decimal point

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