Part E Constants A rigid, uniform, horizontal bar of mass m and length is supported by...

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Part E Constants A rigid, uniform, horizontal bar of mass m and length is supported by two identical massless strings. (Figure 1)Both strings are vertical. String A is attached at a distance d < L/2 from the left end of the bar and is connected to the ceiling; string B is attached to the left end of the bar and is connected to the floor. A small block of mass m2 is supported against gravity by the bar at a distance x from the left end of the bar, as shown in the figure. Throughout this problem positive torque is that which spins an object counterclockwise. Use g for the magnitude of the acceleration due to gravity. Note that critical, as computed in the previous part, is not necessarily positive. If critical <0, the bar will be stable no matter where the block of mass m2 is placed on it. Assuming that m1, d, and L are held fixed, what is the maximum block mass mmax for which the bar will always be stable? In other words, what is the maximum block mass such that critical 0? Answer in terms of m1, d, and L. View Available Hint(s) Hint 1. Requirement of stability If x is calculated to be less than zero, the solution is unphysical. (The bar does not extend there to support it!) The minimum value that x can have is obviously zero. If m is less than the mass that would give critical O then the bar will be stable for any physical value of x. = Figure String B String A mi x L 1 of 1 m2 mmax = Submit xa Xb x xx x Previous Answers Request Answer Part E Constants A rigid, uniform, horizontal bar of mass m and length is supported by two identical massless strings. (Figure 1)Both strings are vertical. String A is attached at a distance d < L/2 from the left end of the bar and is connected to the ceiling; string B is attached to the left end of the bar and is connected to the floor. A small block of mass m2 is supported against gravity by the bar at a distance x from the left end of the bar, as shown in the figure. Throughout this problem positive torque is that which spins an object counterclockwise. Use g for the magnitude of the acceleration due to gravity. Note that critical, as computed in the previous part, is not necessarily positive. If critical <0, the bar will be stable no matter where the block of mass m2 is placed on it. Assuming that m1, d, and L are held fixed, what is the maximum block mass mmax for which the bar will always be stable? In other words, what is the maximum block mass such that critical 0? Answer in terms of m1, d, and L. View Available Hint(s) Hint 1. Requirement of stability If x is calculated to be less than zero, the solution is unphysical. (The bar does not extend there to support it!) The minimum value that x can have is obviously zero. If m is less than the mass that would give critical O then the bar will be stable for any physical value of x. = Figure String B String A mi x L 1 of 1 m2 mmax = Submit xa Xb x xx x Previous Answers Request Answer