Question: Part E Explain why the sigma complex (and the transition state leading to it) is lower in energy for substitution at the ortho and para

Part E

Explain why the sigma complex (and the transition state leading to it) is lower in energy for substitution at the ortho and para positions than it is for substitution at the meta position.

Match the words in the left column to the appropriate blanks in the sentences on the right.

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  • is never
  • 2 carbon with the ethyl group

    2 Superscript circ carbon with the ethyl group

  • 3 carbon with the ethyl group

    3 Superscript circ carbon with the ethyl group

  • ortho or para
  • is
  • meta
  • The key to electrophilic aromatic substitution lies in the stability of the sigma complex. When the electrophile bonds at ortho or para positions of ethylbenzene, the positive charge is shared by the

    The key to electrophilic aromatic substitution lies in the stability of the sigma complex. When the electrophile bonds at ortho or para positions of ethylbenzene, the positive charge is shared by the blank. Bonding of the electrophile at the blank position lends no particular advantage because the positive charge in the sigma complex blank adjacent to, and therefore blank stabilized by, the ethyl group.

    . Bonding of the electrophile at the

    The key to electrophilic aromatic substitution lies in the stability of the sigma complex. When the electrophile bonds at ortho or para positions of ethylbenzene, the positive charge is shared by the blank. Bonding of the electrophile at the blank position lends no particular advantage because the positive charge in the sigma complex blank adjacent to, and therefore blank stabilized by, the ethyl group.

    position lends no particular advantage because the positive charge in the sigma complex

    The key to electrophilic aromatic substitution lies in the stability of the sigma complex. When the electrophile bonds at ortho or para positions of ethylbenzene, the positive charge is shared by the blank. Bonding of the electrophile at the blank position lends no particular advantage because the positive charge in the sigma complex blank adjacent to, and therefore blank stabilized by, the ethyl group.

    adjacent to, and therefore

    The key to electrophilic aromatic substitution lies in the stability of the sigma complex. When the electrophile bonds at ortho or para positions of ethylbenzene, the positive charge is shared by the blank. Bonding of the electrophile at the blank position lends no particular advantage because the positive charge in the sigma complex blank adjacent to, and therefore blank stabilized by, the ethyl group.

    stabilized by, the ethyl group.

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