Question: Part F Substituting your answer from Part E gives the equation ( E 2 E 1 ) ( 2 mc 2 ) = p 2

Part F
Substituting your answer from Part E gives the equation
(E2E1)(2mc2)=p22c2p21c2(E2E1)(2mc2)=p22c2p12c2.
Divide both sides by 2mc22mc2 to find an expression for E2E1E2E1.
Express your answer in terms of p1p1, p2p2, mm, and cc.
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E2E1E2E1=
nothing

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