part.For the given parametric equations, find the points $($x$,$y$)$ corresponding to the parameter values t$=-2,-1,0,1,2.$

$x=6t^{2}6t,y=4^{t1}$

Sciep $1$

$x=6t^{2}6t$

$y=4t1$

Let $f=0.$ Then the coordinates of the corresponding point are found as follows.

$x=6(0{)}^{2}6(0)$

$=$

$y=4^{01}$

$=$

Therefore, the point given by the parametric equations that corresponds to $t=0$ is $(x,n)=1$