Perpendiculars perpendiculars X (A) = 5 (C) 4 = y-1 8 y-1 3 are drawn from...

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Perpendiculars perpendiculars X (A) = 5 (C) 4 = y-1 8 y-1 3 are drawn from points on the line lie on the line z-2 -13 -2 = = -7 x + 2 2 11 (B) y+1_2 -1 3 z-2 2 3 -5 z-2 XNXN || to the plane x + y + z = 3. The feet of (D) 3=3 || = 2 -7 5 For a > b> c>0, the distance between (1, 1) and the point of intersection of the lines ax + by + c = 0 and bx + ay + c = 0 is less than 22, then (A) a+b-c>0 (C) a-b+c>0 (B) a-b+c <0 (D) a+b-c <0 The area enclosed by the curves y = sinx + cosx and y = |cosx - sinx| over the interval 0, [4] 2 (A) 4 (2-1) (C) 2(2+1) (B) 22 (2-1) (D) 22 (2+1) is Four persons independently solve a certain problem correctly with probabilities probability that the problem is solved correctly by at least one of them is 235 21 (B) 256 3 256 (A) (C) (D) 256 253 256 131 1 - 2'4'4'8 - Then the - Let complex numbers a and lie on circles (x - xo) + (y - yo) = r and (x xo) + (y - yo) = 4r, a respectively. If zo = xo + iyo satisfies the equation 2|zo| = r + 2, then |a| = (B) (A) /2 -14-15 (C) (D) 21 3 Perpendiculars perpendiculars X (A) = 5 (C) 4 = y-1 8 y-1 3 are drawn from points on the line lie on the line z-2 -13 -2 = = -7 x + 2 2 11 (B) y+1_2 -1 3 z-2 2 3 -5 z-2 XNXN || to the plane x + y + z = 3. The feet of (D) 3=3 || = 2 -7 5 For a > b> c>0, the distance between (1, 1) and the point of intersection of the lines ax + by + c = 0 and bx + ay + c = 0 is less than 22, then (A) a+b-c>0 (C) a-b+c>0 (B) a-b+c <0 (D) a+b-c <0 The area enclosed by the curves y = sinx + cosx and y = |cosx - sinx| over the interval 0, [4] 2 (A) 4 (2-1) (C) 2(2+1) (B) 22 (2-1) (D) 22 (2+1) is Four persons independently solve a certain problem correctly with probabilities probability that the problem is solved correctly by at least one of them is 235 21 (B) 256 3 256 (A) (C) (D) 256 253 256 131 1 - 2'4'4'8 - Then the - Let complex numbers a and lie on circles (x - xo) + (y - yo) = r and (x xo) + (y - yo) = 4r, a respectively. If zo = xo + iyo satisfies the equation 2|zo| = r + 2, then |a| = (B) (A) /2 -14-15 (C) (D) 21 3

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