PHY 166: EXP.2

Static Equilibrium

CALCULATION AND ANALYSIS

I need you to do points 1 to 4, I provide the information table and the x and y points for the graphs.

1. Draw a picture showing the three forces for Trial 1. (This is sometimes called a free body diagram.) Be sure to label each vector's direction and magnitude. Calculate the component forces for each force vector, F, and F, using equation 2.3

1. Calculate IF, toral and F using equations 2.5 and 2.6, given below.
2. Calculate the % discrepancy of the force calculations using equation 2.4. Repeat steps 2 through 4 using data from trials 2 and 3.
3. In procedure 7, was the system in equilibrium? Justify your results by explicitly showing your calculations.
4. What are the sources of experimental error in this experiment? Do any of these factors help the ring achieve static equilibrium?

*You can find the lab manual for better references on this platform*

Trial 1 FX = Fi. corsos Fy = Fi. SING 1 300 grams = 0:3 kg F = 0. 3 Kg X 9.81 m / s? = 2.943 X 2.943 X COS (O) = 2.943 ( 2.943 , 2.943 ) Y 2. 943 X COSCO) = 2.943 X 2 ) 400 grams = 0.4 kg F = 0 . 4 kg X 4 . 81 / /s = 3.92 X 3.92 X COS ( 60 ) = 10.1433 CO. 433, 3.398 ) Y 3. 92 x SIN ( 60) = 3.398 X 3) 700 groms = 0 . 7kg F= 0.7 Ko X 4.81 m /s= = 6.867 X 6. 867 X COS ( 215.0) = - 5. 625 C - 5. 625 1 - 3.938 ) y 6. 867 X SIN ( 215. 0) =- 3.9383 X yTrial 2 1 ) 300 grams = 0.3 kg F = 0.3 kg X 9. 81 = 2. 943 X = 0.3 x COS (O) = 2.943 ( 2.943, 2.943 ) X = 0. 3x SIN CO) = 2.943 X y 2 ) 400 grams = 0.4Kg F = 0. 4 Kg x 9. 81 = 392 X = 3.92 X Cos ( 45) = 2764 ( 2. 764 , 3:3 35 ) Y = 3.92 X SIN ( 45 ) = 3.335 X 3 ) 700 grams = 0. 7 kg F = 0. 7kg x 4.81 m / s = 6.867 * = 6.876 X COS ( 205.0) = - 6.231 (-6.231 - 2.905) Y = 6. 876 x SIN ( 205.0 ) = -2.905 XTrial s 1 300 grams = 0.3 kg F = 0.3 kg x 9.81 Mls' = 2.943 X = 2.943 X COSCOX = 2.943 * = 2.943 X SINCO) = 2.943 ( 2.943 , 2.943) X y 2) 400 grams = 0.4kg F = 0.4 Kg x 4.81 mls? = 3.92 X = 3.92 X COS ( 45) = 2.764 ( 2. 764, 383.5). * = 3.92 x SIN ( 45 ) = 3.335 X y 3) 750 grams =0.75 kg F= 0.75 Kg x 9. 81 m/2 = 7. 357 *= 7.357 X Cos (166.0) =-7,138 C - 7. 138 , 1.779 ) y = 7.357 X SIN ( 166.0) = 1.779 X Y 4) 500 grams = 0.5 kg - F= 0.5kg x 9. 81 m / s = 4.90 X = 4.905 X COS ( 287.0) = 1.434 y = 4. 905 X SIN ( 287.0) = - 4.690 ( 1.434 - 4.690) X Y