pl: LC-3 assembly code

To start you off with this homework, we are implementing the multiply function! Store the result of the operation in the label ANSWER. Arguments A and B are stored in memory, and you will load them from there to perform this operation. Assume the values of A and B are positive integers. Implement your assembly code in mult.asm. Suggested Pseudocode: a = (argument 1); b = (argument 2); ANSWER = 0; while (b > 0) { ANSWER - ANSWER + a; b--; // note: when the while-loop ends, the value stored at ANSWER is a times b. 3 ::Pseudocode (see PDF for explanation) ; a = (argument 1); ;b = (argument 2); ANSWER = 0; ;; while (b > 0) { ANSWER = ANSWER + a; ; b--; 1 2 3 5 i note: when the while-loop ends, the value stored at ANSWER is a times b. .orig x3000 ::YOUR CODE GOES HERE HALT 23 A B SAW fill 5 fill 15 ANSWER .blkw 1 .end To start you off with this homework, we are implementing the multiply function! Store the result of the operation in the label ANSWER. Arguments A and B are stored in memory, and you will load them from there to perform this operation. Assume the values of A and B are positive integers. Implement your assembly code in mult.asm. Suggested Pseudocode: a = (argument 1); b = (argument 2); ANSWER = 0; while (b > 0) { ANSWER - ANSWER + a; b--; // note: when the while-loop ends, the value stored at ANSWER is a times b. 3 ::Pseudocode (see PDF for explanation) ; a = (argument 1); ;b = (argument 2); ANSWER = 0; ;; while (b > 0) { ANSWER = ANSWER + a; ; b--; 1 2 3 5 i note: when the while-loop ends, the value stored at ANSWER is a times b. .orig x3000 ::YOUR CODE GOES HERE HALT 23 A B SAW fill 5 fill 15 ANSWER .blkw 1 .end