A falling gradient of 4% meets a rising gradient of 5% at station 2 + 450...

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A falling gradient of 4% meets a rising gradient of 5% at station 2 + 450 and with elevation 216.42 m. At station 2 + 350 the underside of a bridge has an elevation of 235.54 m. The two grades are to be joined by a vertical parabolic curve giving 14 m clearance under the bridge. Determine the required length of vertical curve that can satisfy the given condition. Also compute the elevation of invert that shall be located below the lowest point of the curve. The outside diameter of the culvert is 1.2 m and the backfill thickness is 0.5 m. A falling gradient of 4% meets a rising gradient of 5% at station 2 + 450 and with elevation 216.42 m. At station 2 + 350 the underside of a bridge has an elevation of 235.54 m. The two grades are to be joined by a vertical parabolic curve giving 14 m clearance under the bridge. Determine the required length of vertical curve that can satisfy the given condition. Also compute the elevation of invert that shall be located below the lowest point of the curve. The outside diameter of the culvert is 1.2 m and the backfill thickness is 0.5 m.