Question: 20. if P is a variable point such that th ewum of the 14. Let A(2-3), Bi-2,1) be vertices of a triangie ABC. If


20. if P is a variable point such that th ewum of 

20. if P is a variable point such that th ewum of the 14. Let A(2-3), Bi-2,1) be vertices of a triangie ABC. If the centroid of the triangle moves on the line 2x+3y1, then the locus of the vertex C is the line ) 3x + 2 =5 J) 2r + 3y = 4 Jr. MATHEMATICS distances from P to the points A 22) and B (2-2) is 4, then the locus of P represents 1) An ellipse 3) segment of a vertical fine 4) segment of a horizontal line 2) A venical ine 2) 2r -3y =7 4)2x + 3y - 9-0 15 If (pa). (acos8,bsine). (bcos0.asine) are the vertices of a triangle, where e is a parameter, (AP EAMCET 2017) 21. A(2,3) B(3,-5) are two vertices of AABC Oves on the line 2x +y-2-0, then dthe locus of C then the locus of the centroid of the triangle is is 1) x+2y+2=0 -9(a +b}* 2) 2x+y+2=0 1) 3) 2x+ y-2 =0 2) (3e-p + (3y-g = (a+b) 3) ai-a) + y (+b) = p + q 4) (3eep) + (3y+q) = (a+b) 4) 3x +y+2=0 22. p.X.X , and q. y.y-y, at r two arithmetic progression with common difference a and B respectively. Ifa and B are the arithmetic means of x, and y Y %3! 16. The equation of the locus of a point equidistant from points (a,b,) and (ab,) is (a,-air + (b,-b, )y+c=0, the value of C is 1) -- 2) + b - ai - b) 3) af-+- 4 ( +a +b + b}) repsectively, then the locus of P(a,B) is 1) a(x - p) = Bly-q) 2) p(x-a) = q(y-B) 3) a(x-p) = b(y-9). 4) b(x-p) = aly-4) 23. The locus of the point P such that the area of 1. A line passes through a fixed point (a, b) the locus of the foot of the perpendicular on it from origin the APAB is 7, where A(4,5) and B(-2,3) are given points, is EDUC is 1) a straight line 2) a pair of parallel lines 4) an ellipse 1) +y +ar + by =0 2) +y -ar- by =0 3) +y-ar+ by= 0 4) +y +ar- by = 0 3) circle 24. A = (1,2), B = (-1,4) if the axes are rotated through an angle in anticlockwise sense, 12 B. A(0, 5) and B(0, -5) are the points and then the slope of the line AB with refrence to the new axes is AP-PB =8 then the locus of P is 1) V3 2) 5 3) -V5 4) 1) 16-9y +144=0 2) 16x +9y +1 +144 = 0 3) +9y +144 0 4) 16 -9y -144 = 0 25. To eliminate the first degree terns of r'+y 4x-8y+3=0 the origin is to be shifted to 1) (-2, -4) 2) (2, 4) 3) (4, 8) 4) (-4,-8) The locus of the point P which is equidistant from 3r + 4y + 5 = 0 and 9x + 12y + 7 = 0 is 1) a hyperbola 3) a parabola 20. The point to which the axes are to translated to eliminate 'y' term and constant term in the equation y + 8x +4y -2 =0 is 2) an ellipse 1) (3, -2) 2) 3) 4) a straight line KASH FAST TI

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