Question: If the image of the point (-1,3,4) in the plane x-2y = 0 is (x, y Z) then 2, 1) 1 2) 2 3)

If the image of the point (-1,3,4) in the plane x-2y = 0 is (x, y Z) then 2, 1) 1 2) 2 3) 3 4) 4 The planes x= 0, x = a, y = 0, y a, z 0 and z = a form a 1) Parallelopiped 2) Rectangular parallelopiped with distanct edges 3) Cube 4) Tetrahedron :0. Statement 1: The point 4(3, 1, 6) is the mirror image of the point B(1, 3, 4) in the mirror image of the point B(1, 3, 4)in the plane x-y +z 5. Statement 2: The plane x-y + z 5bisects the line segment joining A(3, 1, 6) and B(1, 3, 4). 1) Statement 1 is flase, statement 2 is true. 2) Statement 1 is true, statement 2 is true; statement 2 is a correct explanation for statement i 3) Statement 1 is true, statement 2 is true; statement 2 is not a correct explanation for statement 2. 4) Statement 1 is true, statement 2 is false. Miscllanous: 31. The reflection of the plane 2x -3y +4z -3 = 0 in the plane x-y +z -3 = 0 is the plane 1) 4x -3y +2z -15 0 2) x -3y +2z -15 = 0 3) 4x +3y -2z +15 0 4) 4x +3y +2z +15 0 32. If the plane x+y+z 1 is rotated through an angle 90 about its line of intersection with the plane x-2y +3z 0, then the new position of the plane is 1) x-5y +4z 1 2) x -5y +4z = -1 4) x-8y +7z = -2 Numerical value type questions 3) x -8y +7z = 2 y 33. The plane -++- 12 -1 =1 meets the co-ordinate axes in the points A, B and C respectively. Area of triangle ABC is 34. If (4k,, k, 1) and (4k2, k, 1) are two points lying on the plane in which (2, 3, 2) and (1, 2, 1) are mirror image to each other, then k,k, is equal to 35. The plane x- y-z 2 is rotated through an angle 90 about its line of intersection with the plane x+ 2y + z 2. Then equation of this plane in new position is 5x + 4y + z = k then 5k = 36. Given a = 3i+ j+2k and B=i-2j-4k are the position vectors of the points A and B. Then the distance of the point -i+j+k from the plane passing through B and perpendicular to AB is 37. The ratio in which the line segment joining the points whose position vectors are 2i-4j-7k and -3i + 5j-8k is divided by the plane whose equation is r (i-2j+3k)=13 is m:n then Im+n| 38. A line with positive direction cosines passes through the point P(2,-1,2) and makes equal angles with the coordinate axes. The line meets the plane 2x + y + z 9 at point Q. The length of the line segment PQ =
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