please answer $by$ listing all spaces out

Let A denote the area between the graphs $x+4y=16$ and $x+5=y^2.$ This area can $be$ computed $in$ two different ways. Complete both

descriptions below.

First, the desired area can $be$ expressed $as$ the sum

$A={\displaystyle \underset{a}{\overset{b}{}}}f(x)dx+{\displaystyle \underset{b}{\overset{c}{}}}g(x)dx$

where $a=$

$,b=$

$,c=$

$,$ and

$f(x)=$

$1,$

$g(x)=$

Second, the desired area can $be$ expressed $as$ the single integral

$A={\displaystyle \underset{}{\overset{}{}}}h(y)dy$

where $=$

$,=$

$,$ and

$h(y)=21-4y-y^2$

Both methods give the same answer, namely, $A=$

$\frac{500}{3}$