Question: Please answer both!! Im really confused Consider the following system at equillbrium where H=18.8kJ, and Kc=10.5, at 350K: 2CH2Cl2(g)CH4(g)+CCl4(g) When 0.38 moles of CH4(g) are

Please answer both!! Im really confused  Please answer both!! Im really confused Consider the following system at
equillbrium where H=18.8kJ, and Kc=10.5, at 350K: 2CH2Cl2(g)CH4(g)+CCl4(g) When 0.38 moles of

Consider the following system at equillbrium where H=18.8kJ, and Kc=10.5, at 350K: 2CH2Cl2(g)CH4(g)+CCl4(g) When 0.38 moles of CH4(g) are removed from the equillbrium system at constant temperature: The value of Kc ncreases decreases remains the same The value of Qe is greater than Kc is equal to Kc is less than Kc The reaction must run in the forward direction to reestablish equillbrium run in the reverse direction to reestablish equilibrium remain in the current position, since it is already at equilibrium Consider the following system at equilibrium where H=108kJ, and Kc=77.5, at 600K: CO(g)+Cl2(g)=COCl2(g) When 0.10 moles of COCl2(g) are added to the equilibrium system at constant temperature: The value of Kc ncreases decreases remains the same The value of Qc Is greater than Kc is equal to Kc is less than Kc The reaction must run in the forward direction to reestablish equilibrium run in the reverse direction to reestablish equilibrium remain in the current position, since it is already at equilibrium The concentration of CO will increase decrease

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