Question: PLEASE ANSWER EACH ONE FOR EACH Practice Problem 4: Calculation of Equilibrium Concentrations + H2(g) + 12(g) + 2HI(g) A 1.00-L flask is filled with

Practice Problem 4: Calculation of Equilibrium Concentrations + H2(g) + 12(g) + 2HI(g) A 1.00-L flask is filled with 1.00 moles of Hand 2.00 moles of I. The value of the equilibrium constant for the reaction of hydrogen and iodine reacting to form hydrogen iodide is 50.5 under the given conditions. What are the equilibrium concentrations of Ha, 13, and Hlin moles/L? . Steps: Determine the direction of the reaction Set up ICE table Solve for x, using K Calculate each equilibrium concentration Confirm calculated equilibrium concentrations . Practice Problem 3: Calculating Equilibrium Constant 12(aq) + (aq) = 13(aq) lodine molecules react reversibly with iodide ions to produce triiodide ions. If a solution with the concentrations of land both equal to 0.00013 M before reaction gives an equilibrium concentration of lof 0.000117 M, what is the equilibrium constant for the reaction
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