Question: Please answer in as much detail as possible. 2. (25pt) A plastic slab of 10.0 cm thick at 20C will be located between steel plates

Please answer in as much detail as possible.
2. (25pt) A plastic slab of 10.0 cm thick at 20C will be located between steel plates with surface temperatures of 200C. Estimate the time for the center of the plastic slab to reach 100C. (ksteel = 45 W/mC, Pplaste = 1000 kg/m3, kplaste= 0.10 W/mC, Cp.plastic= 1500 J/kg) 1) Draw the wall and temperature profile with time 2) Define the governing equation 3) Initial and boundary conditions. 4) Calculate the time in seconds
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