Question: Please answer no. 1-2 with complete solution, check the picture above for the guide, thank you! Electric Flux The relationship between electric charge and electric

Please answer no. 1-2 with complete solution, check the picture above for the guide, thank you!

Please answer no. 1-2 with complete solution, check the picture above for

Electric Flux The relationship between electric charge and electric field was also formulated alternatively in Gauss's law (Karl Friedrich Gauss 1777-1855). This is logically equivalent to Coulomb's law, but this was easier to use in finding electric field for symmetrical charge distribution. Gauss's law general statement is expressed as: OF = FB cos 0 where is the electric flux Nm CE is the magnitude of electric field expressed in-, O is the and between the normal line of the surface and electric field lines. and A is the area of a given surfa expressed in m2. Electric flux refers to the amount of electric field lines penetrating a given surface. The electric flux is maximum if the electric field lines are perpendicular to the surface or parallel to the normal line of the surface. The electric flux is zero when the electric field line is parallel to the surface or perpendicular to the normal line of the surface. At a given angle, the electric flux is directly proportional to the component of the electric field lines. PE = EA cos cos 0 = EA DE = EA cos cos 90 = 0 DE os cos e Problem (1): A uniform electric field with a magnitude of E = 400 N/C incident on a plane surface of area A = 10 m and makes an angle of 0 = 30 with it. Find the electric flux through this surface? Solution: electric flux is defined as the amount of electric field passing through a surface of area A with formula be = E . A = E A cos 0 where dot (.) is the dot product between electric field and area vector and 0 is the angle between E and the normal vector to the plane. In this problem, the angle between electric field and normal to the plane is 60 so we get Pe = EA cos 0 = 400 x 10 x cos 30 1/2 = 2000 N.m /C WORKSHEET NO. 3 1. Find the electric flux through the surface with sides of 15 cm X 15 cm shown in the figure below. n . What is the magnitude of electric flux of a constant E of 4N/C in the z-direction through a rectangle with surface area 4m2 in the xy-plane

Step by Step Solution

There are 3 Steps involved in it

1 Expert Approved Answer
Step: 1 Unlock blur-text-image
Question Has Been Solved by an Expert!

Get step-by-step solutions from verified subject matter experts

Step: 2 Unlock
Step: 3 Unlock

Students Have Also Explored These Related Physics Questions!