Please answer number $5$ which is part two to number $4.$

$d=\sqrt[\phantom{2}]{2}a$

$d=\frac{q}{Q}\frac{a}{2}$

$d=\frac{a}{2}$

$d=\frac{q}{Q}\frac{a}{\sqrt[\phantom{2}]{2}}$

$d=a$

$+004($part $1$ of $2)10\mathrm{.}0$ points

Three point charges are placed at the vertices of an equilaterab triangle as shown.

What is the magnitude of the electric force on the charge at the bottom left$-$hand vertex of the triangle due to the other two charges?

$||vec(F)||=\frac{1}{2}\frac{k{q}^2}{a^2}$ go mas the

$||vec(F)||=\frac{k{q}^2}{a^2}$

$||vec(F)||=\frac{2}{\sqrt[\phantom{2}]{3}}\frac{k{q}^2}{a^2}$

$||vec(F)||=\frac{3}{\sqrt[\phantom{2}]{2}}\frac{k{q}^2}{a^2}$

$||vec(F)||=\sqrt[\phantom{2}]{2}\frac{k{q}^2}{a^2}$

$||vec(F)||=\frac{\sqrt[\phantom{2}]{3}}{2}\frac{k{q}^2}{a^2}$

$005($part $2$ of $2)10\mathrm{.}0$ points What is the direction of the electric force on the charge at the bottom left$-$hand vertex of the triangle due to the other two charges?

$006$

$10\mathrm{.}0$ points

Two uncharged metal balls, $x$ and $Y,$ each stand on a glass rod and are touching.