please answer scaling. All answers before are correct. Please use them.

In the commercial production of sugar (sucrose), the product crystals are washed and centrifuged to partial dryness. The crystals are then sent through a rotary dryer where they are contacted with a hot stream of air that reduces the moisture conte from 1.00 wt% to 0.100 wt%. a The ratio of wet sugar to inlet air fed to the dryer is 3.00 kg wet sugar/kg inlet air, The inlet air contains 1.60 mole% water. Weight Percent Water Correct. Weight Percent Water correct Calculate the weight percent of water in the inlet air stream. W2 = 1 % e Textbook and Media Hint m, (kg wet sugar) A kg H,O/100 kg m, (kg wet sugar) C kg H20/100 kg Dryer m3 (kg humid air) B kg H20/100 kg with m, (kg humid air) w, kg H20/100 kg A = 1.00 B = 1.00129 C = 0.100 Refer to the flowchart in the previous question part. Which of the following balance equations or contraints are correct. Choose four: three balance equations and one constraint. m (1-1.00/100) = m3(1-0.100/100) mi/m3 = 3.00 m3 (1-1.00129/100) = m (1-W4/100) mi(1.00/100) + m2 (1.60/100) = 2123 (0.100/100) + X4 M4 mi/112 = 3.00 mi(1-1.00/100) = m2 (1-0.100/100) mi(1.00/100) + m3 (1.00129/100) = m (0.100/100) + W4/100 mg Take as a basis 100.0 kg of wet sugar fed to the dryer. Calculate the following: The mass of humid air entering the process (mg): 33.333 kg The mass of wet sugar leaving the process (m2): 99.09910 kg The mass of humid air leaving the process (ma): 34.23390 kg The mole fraction of water in the air leaving the process: 0.056738 caling X This is a unit conversion and scaling problem. If 1000 tons/day of of sugar containing 0.100 wt% water is to be produced, at what rate (bm/h) is water evaporated from the feed stream of wet sugar? 1178.45 Ibm/h Hint Save for Later Attempts: 2 of 10 used Submit