Please answer step 3 clearly and concisely

Qs The acceleration function (in m/s?) and the initial velocity 1(0) (in m/s) are given for a particle moving along a line. a(t)=2t+4, v(0)=-12, 0sts5 (a) Find the velocity at time , (b) Find the distance traveled during the given time interval. Step1 I (a) Find the velocity at time Recall that the acceleration of an ebject is a(t) = v'(t). Therefore, to find v(t) given a(t), the following relationship can be used. ja(r) dt=u(e) We are given a(t) = 2t + 4. Therefore, we have the following. vie) = | 5 N T & a u = + e = +C v | Step 2 We have determined that v(t] = + 4 + C. We must now determine the value of C. We are given that v(0) = 12. Using this allows us to solve for C as follows. i) = +at+cC v(0) = 02 +4(0) + C -12 c Substituting = 12 into the velocity function gives the following result (in m/s). vty =+ 4 12 m/s |[PHdt-12 | (b) Find the distance traveled during the given time interval. Recall that the total distance traveled from time , to time t, is given by the following. ./fz 1 In a previous step we determined that v(t) = + 4t 12. We wish to find the total distance traveled over the interval 0