Question: please answer the following I give an example below Please follow the method of the example thank you Solutions: a. vafter Is d. f from
please answer the following
I give an example below
Please follow the method of the example
thank you



Solutions: a. vafter Is d. f from origin to maximum height use: vr = Vi - gt Note: An object thrown upward will reach a certain point (maximum vy=20 m/s - (9.8 m/s )(1.0s) height) where it will momentarily vy = 20 m/s - 9.8 m/s stop and then start to move vy = 10.2 m/s downward. At this point, vy = 0. b. v after 2s Use: W/ = VI - gt use: v/ = v1 - gt Manipulating the equation, vy=20 m/s-(9.8 m/s2)(2.0s) vy = 20 m/s - 19.6 m/s t = V1 = Uf vs = 0.4 m/s 1= 20 m/s - 0 c. d after Is 9.8 m/s use: t= 2.04 s d = vit - 9 2 d = 20m/s(1.0s) - (9.8 m/s?)(1.0s)2 e. d from origin to maximum height 2 use: d = vit - d = 20m - 4.9 m d = 15.1 m d = 20m/s (2.04 s) - (9.8 m/s?)(2.04s)2 (positive sign denotes that the object is 2 d = 40.8 m - 20.40 m moving upward) d = 20.4 mummple Problem 1. A stone is dropped from the top of a building and falls freely from rest. What is its position (height) and its velocity after 1.0s, 2.0s, and 3.0s? use: To find for the position (height), we will c. Find h after 3.0s h = vit-9to h = 0(3.0s) - (9.8 m/s)(3.0s)2 Know that initial velocity (vi) = 0 h = 0- 88.2 m 2 a. Find h after 1.0s h = -44.1 m or 44.1 m downward h =0(1.0s) - (9.8 m/s)(1.0s)2 To find for velocity (vr), we will use: 2 h =0-9.8 m v/ = Vi - gt a. Find wy after 1.0s h= -4.9 m vy= 0 - (9.8 m/s )(1.0s) (negative sign denotes downward direction) = - 9.8 m/s b. Find h after 2.0s b. Find vy after 2.0s h = 0(2.0s) - (9.8 m/s )(2.0s)2 v=0 - (9.8 m/s ) (2.0s) 2 vy = - 19.6 m/s h =0-39.2m c. Find wy after 3.0s 2 v=0 - (9.8 m/s )(.0s) h = - 19.6 m or 19.6 m downward vy= - 29.4 m/s Sample Problem 2. A boy threw a ball upward with an initial velocity of 20 m/s and was able to catch it before it reached the ground on its return. a. What was the ball's velocity after Is? b. What was the ball's velocity after 2s? c. What was its displacement after Is? d. How long did it take the ball to reach its maximum height? e. How far was the maximum height from the starting point? Given: Vi = 20 m/s Find: a. v after Is b. vafter 5s c. d after Is d. t from origin to maximum height e. d from origin to maximum heightActivity 1: Problem Solving Directions: Show your complete solutions for the following worded problems. 1. A flower pot falls a window of a three-storey apartment. How far has it fallen after 2 seconds? What is the pot's velocity after I s of fall? after 2 seconds of fall? 2. A brick falls freely from a high scaffold and hits the ground after 3.5 seconds. How high is the scaffold? What is the velocity of the brick just before hitting the ground? 3. Alice thrown a ball upwards vertically from the roof of a building. The ball leaves her hand at a point level with the roof railing with an upward speed of 15 m/s. On its way back down, it just misses the railing. Find (a) the ball's position and velocity 1.0 s and 4.0 s after leaving her hand; (b) the ball's velocity when it is 5.0 m above the railing; (c) the maximum height reached
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