Question: Please answer the question 5 5) Given the following program: #include > int main(void) { char ch; ch=C; ch=ch+1;/ line 6/ printf(Now ch =% cln,

Please answer the question 5 5) Given the following program: \#include >Please answer the question 5

5) Given the following program: \#include > int main(void) \{ char ch; ch=C; ch=ch+1;/ line 6/ printf("Now ch =% cln", ch); return 0 ; 3 Please explain the type conversion of viable ch in the statement on line 6 during the running

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