Question: please answer these questions my proffessor give me wrong because who answer it for me in chegg last time I will give you what he

please answer these questions my proffessor give me wrong because who answer it for me in chegg last time I will give you what he said

the wrong answers :




1. Convert 103.214 ()2 ( 10 =( ) 16 (Step by Step) 2. Compute 111001010000 / 11011 by binary division (Step by Step) ,/ Brother, the steps for computing base 16 to base 4 is wrong and the steps for the Binary division. Please submit the right steps and i will give you full mark Date: __/_/ (103:21) 44 To convert into base 7 first we need to Convert base 10. ( (103.21) 4 = 4 x 1 + 4x0 + 4x3 + 4 x2 + 9x 16 +0+ 3 + 2 + 1 ( 16 19 +0.5 t o.0625 =(19.5625) 10 We have (19.5625)40 first convert 19 to base 7 2-5 -; (19110 = (25)7 Now we have to cakulate, 0.142 0.020 80, 3x5'+ 6x7? + 3x3 +6x74 0.0Q2 +3x75+6x70 74 = 0.0004 o. 562 - = 2 9 - a (19.5625) 10 = (25-363627 ( ) ( 2 ) 16 119 313 (13916 0 we have take I point precision because we muldsplied hy 16!. (19-5625)10 - (13.99.16. We can Convpet decimal to base 7 by using this step also . ( 19.5625 ) 10 = ? first_multiply wito 24 aud._-hen_take_u_point preusloo (19.5625) x1" 4.6 9 69.5 4.6970 Then divide by 7 and concider_remainders 146970)10 (252640) 1 (19562.5ho. (250_3640) Date: _/_/ Binary Division 111001010000 11011 first convert it to becimal 11001010000 = 3664 11011 = 27 3664 % 27 Quotient = 135 Remainder 191 Now we convert it to binary, Remainder Quob cut 2135 2161-1 2119 33 ) 2 2 tb- 2 214 + -D o 212-0 0 o 2 e + on Quotient-_1000011 Renainder i 1001|
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