Question: Please answer using the above table How long does it take to read an 800 KB file with the same 48X CD reader? An analysis

 Please answer using the above table How long does it takePlease answer using the above table

How long does it take to read an 800 KB file with the same 48X CD reader? An analysis of your data needs shows that you will have 1170 GB of information. It is important that your system not stop due to the simple failure disk drive. There is a good deal on 500 GB disk drives. How many drives and what organization would best support your needs? If you expected only 145 GB of data, how would you organize the storage system and how many 360 GB disks would you need? Imagine you are designing a disk drive. For a given rotational speed in revolutions/minute, R, the time in seconds for the disk to rotate once is 60/R. The average rotational delay would be 60. If there are 64 blocks per track each containing 4KB of data, the 2R 60 transfer time for a block would be 64R. The seek time is 6.l milliseconds. The average time to read 4 KB of data is time = 0.0061 + 60 + 60 The faster the rotation speed, R, the shorter the read 2R 64R time. It costs more to make the disk spin faster. Assume it costs $10 to build a disk motor plus $0.001 for each revolution per minute. This gives a cost formula of cost = 10 + 0.001 middot R. We want to find the best cost * time product. What is the value for R that produces the minimum cost * time? How long does it take to read an 800 KB file with the same 48X CD reader? An analysis of your data needs shows that you will have 1170 GB of information. It is important that your system not stop due to the simple failure disk drive. There is a good deal on 500 GB disk drives. How many drives and what organization would best support your needs? If you expected only 145 GB of data, how would you organize the storage system and how many 360 GB disks would you need? Imagine you are designing a disk drive. For a given rotational speed in revolutions/minute, R, the time in seconds for the disk to rotate once is 60/R. The average rotational delay would be 60. If there are 64 blocks per track each containing 4KB of data, the 2R 60 transfer time for a block would be 64R. The seek time is 6.l milliseconds. The average time to read 4 KB of data is time = 0.0061 + 60 + 60 The faster the rotation speed, R, the shorter the read 2R 64R time. It costs more to make the disk spin faster. Assume it costs $10 to build a disk motor plus $0.001 for each revolution per minute. This gives a cost formula of cost = 10 + 0.001 middot R. We want to find the best cost * time product. What is the value for R that produces the minimum cost * time

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