Question: Please answer with detailed explanation 1/2 ICS IA VECTORS The vector ax(bxa) is: to a 14 3. 2) Perpendicular to b 1) Perpendicular 15 4)

Please answer with detailed explanation

1/2 ICS IA VECTORS The vector ax(bxa) is: to a 14 3.

1/2 ICS IA VECTORS The vector ax(bxa) is: to a 14 3. 2) Perpendicular to b 1) Perpendicular 15 4) Perpendicular to both a and h 3) Null vector 1. If - B-C then determine the angle between i and R 4. A +B -C A +B -C -1 2) 0 = sin 2 AB %3D 1) e= cos 2 AB %3D 2+B -C A + B -C 4) 0 = cot 2 AB %3D -1 3) 0=tan 2 AB 5. Find the area of the triangle formed by the tips of the vectors a=i -j-3k, b= 4i -3i+. 1) 3.2 sq.units 2) 6.4 sq.units 3) 12.8 sq.units 4) 1.4 sq.units projection of a onb projection of b on a 6. If a = 2i+3j+6k and b=31+ 4j, then 1) 7/5 2) 5/7 3) 4/9 4) None 7. If a,b,c are three unit vectors such that a+b+C3D0, then a.b+b.c+c.a is equal to 1) -1 2) 3 3) 0 4)-3/2 8. A particle whose speed is 50 m/s moves along the line from A(2,1) to B(9,25). Find its velocity vector in the form of ai+bj 1) 2(7 +24) 2) 7 + 24j 3) 11i+26j 4) 8i+24 9. A+B=2i and A-B= 4i then angle between A and B is 1) 180 2) 143 3) 530 4) 37 10. Given the vectors A = 2i + 3j-k; B=3i-2j- 2k & C = pi+ pj+ 2pk find the angle between (A-B)&C -1 1) 0= cos V3 V3 2) 0= cos -1 -1 V2 3) 0= cos 3 4) none of these 11. A force of 35 N acts in the direction parallel to 2i+3j+6k and it displaces a body from (1m, 0m, 3m) to (3m, 4m, 1m)find the work done. 1) 20 J 2) 22J 3) 11J 12. If AxB= 0 and A.B=-AB the angle between A andB is: 4) zero 1) 0 TC 2) 4. 3) 4) Tt 13. The resultant of A and B makes angle a with A and B with B. Then: 1) a

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