please answers both.

(1 point) This question concerns the DES IP box. Please enter all answers as strings of 0 's and 1 's. Consider the 64 bit DES block below. 0000000000000100001000001001000000000000000000000000000000100000 Suppose that this is the initial input to DES. What will the block look like after the initial permutation (IP) is applied? If we apply the P1 transformation to the above, what will the result be? (4 points) In this problem we will work through a round of DES. For notational simplicity, assume it is the first round. Please enter all answers as strings of 0 's and 1 's. The input is the 64 bit block 0000100000000001000000000000010000000000000000000000000100000100 Suppose that the subkey for the current round is this 48 bit number: 000001000000000000000000000000000000000000000000 What does the 64 bit state look like after the IP transformation is applied to the input? Now find L0 and R0, the left and right halves of the state. L0= R0= What is the result of applying the expansion box to R0 ? E(R0)= What is the result of XORing the subkey with E(R0) ? k0E(R0)= We now apply the S-box transformation. S(k0E(R0))= Finally we apply the permutation box to complete the function f. Finally we apply the permutation box to complete the function f. f(R0)=P(S(k0E(R0)))= We can now compute the state of DES going into the next round. L1=R1=