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2 22 Let's compute the lim 3-2 sin(x - 2) Let's see what happens if we take the limit of the numerator and denominator: lim (z? - 21) = 1-2 lim (sin(x - 2)) = 2-2 So we have a limit of indeterminant type O none of the above so we will try to use L'H rule. 2 - 2x (x2 - 22) So instead of working with lim we can take the limit of lim 2+2 sin(x - 2) 1-2 (sin(ar - 2))' where (r? - 2x)' = (sin(x - 2))' (22 - 22) By computing the limit we get that lim 2+2 (sin(x - 2))' ? - 2x Thus by L'H Rule we get that lim 1-2 sin(x - 2) Submit