please complete both of these tables TABLE 1. Pulley's Moment of Inertia, I (T) = 0.200m, h= 1m m (kg) (t) (s) (a) h 2(t) (m/s) (a) = (a)/(r) (rad/s) Tappl= m x (9.8-(a)) x (r) (Nm) 0.250 m (kg) t(s) (a) h 2t 0.020 (m/s) 3.070 (a) = (a)/(r) (rad/s) 0.030 2.380 Tapplmx (9.8 - (a)) x (r)

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please complete both of these tables TABLE 1. Pulley's Moment of Inertia, I (T) = 0.200m, h= 1m m (kg) (t) (s) (a) h 2(t) (m/s) (a) = (a)/(r) (rad/s) Tappl= m x (9.8-(a)) x (r) (Nm) 0.250 m (kg) t(s) (a) h 2t 0.020 (m/s) 3.070 (a) = (a)/(r) (rad/s) 0.030 2.380 Tapplmx (9.8 - (a)) x (r) (Nm) TABLE 2. Pulley and TWO attached masses' Moment of Inertia, 12 M (kg) RM (m) 0.075 0.040 0.1 2.074 Plot Tappl, on vertical -axis, vs. (a), on horizontal -axis. Determine slope I and intercept bd (r) f. Obtain the effective friction f = b/(r)| NOTE: linear acceleration is (a) in m/s and angular acceleration is (a), "alpha", in rad/s. 1.355 0.050 0.120 1.891 1.259 0.060 0.140 1.685 1.159 0.160 1.097 Styles 0.100 1.316 1.051 0.180 0.200 1.228 NOTE: add masses M by pairs, on opposite directions to stabilize the wheel, avoiding extra torques to the system and recoiling. 0.120 1.002 Plot Tappl vs. (a)m, and determine slope I, where I is the moment of Inertia, and intercept bef (r) f. Obtain the effective friction f.

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