Please consider a system with the following characteristics: - Phyiscal memory 4GB(232 Bytes) - Frame size 4KB(212 Bytes) We assume that process P1 requires a logical address space of 230KB. Further, we assume that the OS allocates page P to frame F+1.024 for this process. Note that 1KB=1024 Bytes. Please answer all questions below, and show all steps in your solution. a) What is the virtual address (P-No., Offset) and the physical address (F-No., Offset) of P1's logical address: 232023? b) What is the exact physical address of P1 's. Hence the combination of the F-No., and the offset? c) What is the internal fragmentation (in bytes), if any? d) How many frames does this system have? e) How many bits are required for indexing the page table, and how many bits for the offset