Please could you answer 2.4 question using matlab and follow the instructions in the picture. There's a matlab ODE example is below.

%% Name : %% Cour3e: BME 748, Cellular and Molecular Bioengineering Date : %%% De3cription : Brief description/overview of code goe3 here Matlab Ver3ion 2016b Version Control variable/Parameter Li3t %% Parame ter3 prm =[8.0 20 k1 k-1 k2 11]; Initial condi tion3 S0=15.0; % Unit3 C0=0.0; % Units 3et numerical accuracy option3 options ode 3 et ( ' RelTol", le-6, 'Ab3To1' , 1e-9) ; = 30ive with 3tiff-3y3tem 30iver ode 153. Note: read about Matlab 's ther %%% ODE 30lver3 e.g., de 45 %%% [note : x(1)=s, x(2)=E, X(3)=C, X(4)=P] [T,X) = ode 153 (@ode 3y3ten, [0:1: 100], [S0,E0, CO , P0],options,prn); S = x(:,1); E = x(:,2); C = x(:,3); P = x(:,4); plot example plot (T, C),axis ([o 50 0 0.08]) xlabel 'Independent Variable (units) ")ylabel ('Dependent Variable (units) ')title ('Plot Title Goes Here) function dXdT = odesy3tem(T,X, prm) parameter3 k1 = prm (1); = prm (3) ; variabl e3 k2 3 = x(1) ; e = X (2); c = x(3); p = X(4); the differential equation3 dXdT = zero3 (4,1) ; a column vector dXdT (4) k2 * c ; = end %% Name : %% Cour3e: BME 748, Cellular and Molecular Bioengineering Date : %%% De3cription : Brief description/overview of code goe3 here Matlab Ver3ion 2016b Version Control variable/Parameter Li3t %% Parame ter3 prm =[8.0 20 k1 k-1 k2 11]; Initial condi tion3 S0=15.0; % Unit3 C0=0.0; % Units 3et numerical accuracy option3 options ode 3 et ( ' RelTol", le-6, 'Ab3To1' , 1e-9) ; = 30ive with 3tiff-3y3tem 30iver ode 153. Note: read about Matlab 's ther %%% ODE 30lver3 e.g., de 45 %%% [note : x(1)=s, x(2)=E, X(3)=C, X(4)=P] [T,X) = ode 153 (@ode 3y3ten, [0:1: 100], [S0,E0, CO , P0],options,prn); S = x(:,1); E = x(:,2); C = x(:,3); P = x(:,4); plot example plot (T, C),axis ([o 50 0 0.08]) xlabel 'Independent Variable (units) ")ylabel ('Dependent Variable (units) ')title ('Plot Title Goes Here) function dXdT = odesy3tem(T,X, prm) parameter3 k1 = prm (1); = prm (3) ; variabl e3 k2 3 = x(1) ; e = X (2); c = x(3); p = X(4); the differential equation3 dXdT = zero3 (4,1) ; a column vector dXdT (4) k2 * c ; = end