In EE we use I and i for current variables so we use j to represent the square root of minus one that you are probably more familiar with as i. Given: Z1 52 + 43 and Z2 = 4-j3 1. Find the sum Z1* + Z2. (2 points) (Note: the operator means "complex conjugate.") 2. Find the difference Z1-Z2 (2 points) 3. Find the product Z1* x Z2* (2 points) 4. Find the ratio Z1/(Z1 + Z2) (2 points) 5. Find the solution to the simultaneous equations: (8 points) (3+j2) X + (6/30) Y = 22-30 (4+j2) X (3+j2) Y = 5