Please Do B and C using Python and please verify the answers with your programme

If a water hose with initial water velocity $v$ is aimed at angle $$ with respect to the ground

to hit a target of height $h,$ then the horizontal distance $x$ from nozzle to target satisfies the

quadratic equation

$\frac{g{x}^2}{2v^{2}co{s}^2()}-tan()x+h=0,$

where $g=9\mathrm{.}8065\frac{m}{s^2}$ is the acceleration due to gravity.

a$)$ How do you interpret the two roots of this quadratic equation?

b$)$ Assuming that $v=20\frac{m}{s},$ and $h=13\mathrm{.}5m,$ use a routine for solving nonlinear

equation to find the maximum distance $x$ at which the target can be hit for $=70$;

c$)$ Use a one$-$dimensional routine to find the angle $$ for which the distance $x$ is

maximum.