Please do not copy the answer from old answers already posted on chegg. Answer the question with complete steps.

= 1. We know that, if we meet the EOQ assumptions, the optimal order quantity is given by the 2K Q* formula h . This formula is obtained by finding the Q that minimizes a function that hQ CQ) represents the sum of ordering and holding costs + 2. We call such Qas Q* (a) The optimal ordering and holding cost C*- the one we will have to pay when we order the optimal quantity can be written by plugging the optimal Q into the cost function C(Q), i.e., C* hQ* + 2 Show that C = V2KAh. You can do that by plugging the formula for Quinto Cand doing some algebra. = 2 = (b) Suppose that a new person placed a non-optimal order of a times the optimal quantity (Q = a Q*). For example, if the non-optimal order was 50% larger than Q*, then a = 3/2. Note h(aQ*) Ca + that the resulting cost Ca can be easily written as (aQ*) Show that Ca = (2a + ?) C*. The algebra is pretty similar to the one of the previous question. (C) How much higher than C* would the resulting cost Cabe if I mistakenly order 50% more than the optimal amount? Give the answer in percentage. Would the cost be 50% higher, 20% higher, how much higher