PLEASE DO NOT RUN OR RECREATE THE PROGRAM.

I NEED TO SEE HOW THE LOOP WORKS BY MANUAL COMPUTATION.

CAN SOMEONE PLEASE manually SHOW HOW THE FOR LOOP AND IF PRODUCES THE OUTPUT 2, 5, 9 n=3

Type the program's output #include int main(void) { int stop; int result; int n; Input 9 Output scanf("%d", &stop); result = 0; { for (n = 0; n stop) { printf("n=%d", n); printf(" "); break; } printf("%d", result); printf(" "); } 2 3 4 5 6 7 n=6 return 0; X When result > 9, a break statement executes. The rest of the loop body is skipped, and the loop exits. 2 3. 4. Yours 5 6 7 n=6 2 5 9 Expected n=